Question

G(x) = –16x + x2 in vertex form.

Answer 1

`g(x)=(x-8)^2-64`

Explanation:

The given function is;

`g(x)=-16x+x^2`

This is the same as;

`g(x)=x^2-16x`

Add and subtract the square of half the coefficient of x.

`g(x)=x^2-16x+(-8)^2-(-8)^2`

Observe that the first three terms is a perfect square trinomial.

`g(x)=(x-8)^2-64`

The vertex form is
`g(x)=(x-8)^2-64`

The vertex (8,-64)