49.4k views
4 votes
When the pressure that a gas exerts on a sealed container changes from 811 mm Hg to 415 mm Hg, the temperature changes from 33.0°C to _ °C?

User Amia
by
6.3k points

2 Answers

7 votes

Answer:

-116.42°C

Step-by-step explanation:

User NIrav Modi
by
6.5k points
5 votes

Answer:

-116.42°C

Step-by-step explanation:

According to pressure law which states that the pressure of a fixed mass of a gas is directly proportional to its absolute temperature at constant volume.

Therefore;

P1/T1 = P2/T2

P1 = 811 mmHg

P2 = 415 mmHg

T1 = 33°C + 273°C = 306 K

Therefore;

T2 = P2T1/P1

= (415 × 306)/ 811

= 156.58 K

Therefore; temperature = 156.58 - 273 = -116.42°C

User Seanplwong
by
6.2k points