Answer with explanation:
Probability of getting shoot from free throw line= 80% =0.80
Probability of not getting shoot from free throw line = 100% - 80% = 20% = 0.20
A student attempt throwing ,twice from free throw line.
A= First Attempt
B= Second Attempt
→If Events , A and B are Independent,then Probability of A and B is given as
P (A ∩ B)= P(A) × P(B)
→And,Conditional probability of event A has definitely occurred and then probability that event B will occur,when these two events A and B are not Independent, is given by:
![P((B)/(A))=(P(B\cap A))/(P(A))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hb7n7iz2ytvid45gl60wygtsqqzgd9xqh6.png)
Option 4: The conditional probability of Event B given Event A is P(B|A)=P(A and B)/P(A) when two events are not independent.