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18 votes
18 votes
How many terms are there in the series 7+21+15+19+.....+79?
anybody can answer these .​

User Master Styles
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1 Answer

11 votes
11 votes

Answer:

7+21+15+19+.....+79

Here 21 be replaced by 11.

Now., common diffrence btw terms , d = 11-7 = 4

first term , a = 7

Last term , l = 79

number of terms = ( a + l ) ÷ d

=( 7 + 79 ) ÷ 4 = 86 ÷ 4 = 21.5 { It cannot be in decimal }

There's some mistake in the terms you provided please check your question again...

User Hubrik
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