Question

What is the centripetal acceleration of a small laboratory centrifuge in which the tip of the test tube is moving at 19.0 meters/second in a circle with a radius of 10.0 centimeters? A. 1.82 × 102 meters/second2 B. 3.61 × 103 meters/second2 C. 5.64 × 103 meters/second2 D. 2.49 × 103 meters/second2 E. 1.18 × 103 meters/second2

Answer 1

The Answer Is...............:

Answer 2

Answer:
`3.61(10)^(3) (m)/(s^(2))`

The centripetal acceleration
`a_(c)` of an object moving in a uniform circular path is given by the following equation:

`a_(c)=(V^(2))/(r)`

Where:

`V=19m/s` is the velocity

`r=10cm=0.1m` is the radius of the circle

`a_(c)=((19m/s)^(2))/(0.1m)`

`a_(c)=3610m/s^(2)=3.61(10)^(3)m/s^(2)`