Question

Find center and radius
(x-3)^2+y^2=8

Answer 1

Center: (3, 0)

Radius: 2√2

Explanation:

The equation of a circle in standard form:

`(x-h)^2+(y-k)^2=r^2`

(h, k) - center

r - radius

We have the equation:

`(x-3)^2+y^2=8\to(x-3)^2+(y-0)^2=(\sqrt8)^2`

Therefore

the center:
`(3,\ 0)`

the radius:
`r=\sqrt8\to r=√(4\cdot2)\to r=\sqrt4\cdot\sqrt2\to r=2\sqrt2`