2 Answers

Sir Hally · Answer 1 · 2020-07-25T08:10:46+0000

Answer:

B. 3x^2 - 2x - 1.

Explanation:

(f + g)x = f(x) + g(x)

= -4x + 3 + 3x^2 + 2x - 4

Adding like terms we get the answer:

= 3x^2 - 2x - 1.

Iafonov · Answer 2 · 2020-07-29T15:54:00+0000

Hello!

The answer is:

B.
(f+g)(x)=3x^(2) -2x-1

To solve the problem, we need to add/subtract like terms. The like terms are the terms that share the same variable and the same exponent.

For example:

x^(2) +3x^(2) +5x^(3)=4x^(2)+5x^(3)

We were able to add the terms that were squared since both shares the same variable and the same exponent.

So, we are given the functions:

$f(x)=-4x+3\\g(x)=3x^(2) +2x-4$

Now, we are asked to calculate (f+g)(x) which is also equal to f(x) + g(x).

Then, calculating we have:

$(f+g)(x)=(-4x+3)+(3x^(2) +2x-4)\\\\(f+g)(x)=3x^(2) -4x+2x+3-4\\\\(f+g)(x)=3x^(2) -2x-1$

Hence, the answer is:

B.
(f+g)(x)=3x^(2) -2x-1

Have a nice day!