Question

I ONLY GOT ONE SHOT SO PLS HELP, IM STUPID! ANSWER IF YOU KNOW IT. OR AT LEAST TAKE A LOOK!!!!!!!! ( 2 QUESTIONS)

1. A rectangular trampoline measures 15 meters by 18 meters. A pad of constant width is placed around the trampoline so that the total area is 340 square meters.

What is the width of the pad?

MY GUESS IS 1 METER

2.
Use the quadratic formula.

2x^2−5x−9=0

Enter the solutions, in simplified radical form, in the boxes.

x =
or x =

Answer 1

Part 1) The width of the pad is
`1\ m`

Part 2) The solutions are

`x=\frac{5(+)√(97)} {4}` and
`x=\frac{5(-)√(97)} {4}`

Explanation:

Part 1)

Let

x----> the width of the pad

we know that

`(15+2x)(18+2x)=340`

Solve for x

`270+30x+36x+4x^(2) =340\\ \\4x^(2)+66x-70=0`

Solve the quadratic equation by graphing

The solution is
`x=1\ m`

see the attached figure

Part 2) we have

`2x^(2) -5x-9=0`

we know that

The formula to solve a quadratic equation of the form
`ax^(2) +bx+c=0` is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`2x^(2) -5x-9=0`

so

`a=2\\b=-5\\c=-9`

substitute in the formula

`x=\frac{5(+/-)\sqrt{-5^(2)-4(2)(-9)}} {2(2)}`

`x=\frac{5(+/-)√(97)} {4}`

`x=\frac{5(+)√(97)} {4}`

`x=\frac{5(-)√(97)} {4}`