Question

Find the period of the function. y=3 sin x/8

Answer 1

The period of given function is
`Period = 16\pi`

So, Option B is correct.

Explanation:

In this question we need to find the period of the function y= 3 sin x/8

The formula used to find period of function is:
`(2\pi )/(b)`

We need to know the value of b.

To find the value of b we compare the standard equation with the equation of function given.

Standard Equation: y = a sin(bx - c) +d

Given Equation: y= 3 sin(x/8)

Comparing we get:

a= 3

b= 1/8

c= 0

d=0

So, we get the value of b i.e 1/8. Putting it in the formula to find period of given function.

`Period = (2\pi )/(b)`

`Period = (2\pi )/((1)/(8))`

Solving,

`Period = 2\pi *8`

`Period = 16\pi`

So, the period of given function is
`Period = 16\pi`