Question

F(x)=3(x-5)^2+6

how do you find the vertex of this function?

what is the vertex of this function?

Answer 1

Vertex = (5, 6)

Explanation:

f(x) = 3(x - 5)² + 6

First, the coefficient of x² is positive, therefore it has a minimum point.

To find the vertex,

we match the equation with the format (x - h)² + k.

The vertex is at ( h, k)

Vertex = (5, 6)