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Find the first four iterates of the function f(x) = x2 with an initial value of x0 = -1.

a.
1, 1, 1, 1
c.
-1, -1, -1, -1
b.
1, -1, 1, -1
d.
-1, 1, -1, 1


Please select the best answer from the choices provided

User Enzero
by
8.3k points

2 Answers

3 votes

Answer:

A. 1, 1, 1, 1

Explanation:

We start with x0 = 1

x0 = -1 => f(x) = x² = (-1)² = 1

x1 = 1 => f(x) = x² = (1)² = 1

x2 = 1 => f(x) = x² = (1)² = 1

x3 = 1 => f(x) = x² = (1)² = 1

x4 = 1 => f(x) = x² = (1)² = 1

User Heinz Kessler
by
7.1k points
3 votes

Answer:

a. 1, 1, 1, 1

Explanation:

We'll use the formula f(x) = x² for each iteration. The output of the first iteration will be come the input of the second iteration, and so on.

We start with x0 = 1

x0 = -1 => f(x) = x² = (-1)² = 1

x1 = 1 => f(x) = x² = (1)² = 1

x2 = 1 => f(x) = x² = (1)² = 1

x3 = 1 => f(x) = x² = (1)² = 1

x4 = 1 => f(x) = x² = (1)² = 1

User Lakeysha
by
8.9k points

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