Answer:
The variation equation is
![f = \frac{k.m_1.m_2}{ {r}^(2) }](https://img.qammunity.org/2020/formulas/mathematics/middle-school/959c5ftf8sqjc687lq45nsxyewiqze6gc1.png)
Explanation:
From the question, the two masses are
![m_1 \: and \: m_2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/henfzibr8doung0lum6kq68zjr5pzf2abq.png)
This implies that the product of the two masses
![= m_1 * m_2 = m_1.m_2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rzcdw0rwt80toyhp6ubp2de17i6tigyvxq.png)
Moreover, the force,f varies directly with the products of the two masses
![\implies \: f\propto m_1.m_2....eqn.1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u301wywkinjn6hzix8dvaoy646h0yzqak5.png)
Also, the force varies inversely with the square of the distance,r
![\implies \: f\propto \frac{1}{ {r}^(2) }.......eqn.2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kixluqb62tcn7fvjm773wgtw2o7u4bib2z.png)
Joining equation 1 and 2, we got
![\implies \: f\propto \frac{1}{ {r}^(2)} * m_1.m_2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1w029jpuuldhjz0nwn8rwfszvw2gxzth78.png)
![\implies \: f \propto\frac{m_1.m_2}{ {r}^(2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ebgsodrajnd0le32uwjxqqj8ue1pys7waz.png)
But the constant of variation is k
Multiplying the right hand side of the equation by k, we got
![\implies \:f=\frac{k.m_1.m_2}{ {r}^(2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/muebkfqtygyf8zbahjdp4iyt5jhgokmv3j.png)