ANSWER
C)
![{x}^(2) + {y}^(2) = 10](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zauhjt5otllj98rhd2ndxgp45uwp9wbdwg.png)
Step-by-step explanation
The center of the circle is (0,0).
The circle passes through (-1,-3).
The radius can be obtained using the distance formula:
![r = \sqrt{(0 - 1)^(2) + {(0 - - 3)}^(2) } = √(10)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/juu7dejnee518kzmgag6c707rahb8ohztf.png)
The equation is given as:
![( {x - h)}^(2) + ( {y - k)}^(2)= {r}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/28bafx1h5osbzbilas46hkgxb42gthe0bx.png)
Where (h,k) is the center and r is the radius.
This implies that;
![( {x - 0)}^(2) + ( {y - 0)}^(2)= {( √(10)) }^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aba17xwo2sel1gy72wb8wkhcvdcsc4ziow.png)
![{x}^(2) + {y}^(2) = 10](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zauhjt5otllj98rhd2ndxgp45uwp9wbdwg.png)