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The equation h(t)=-16t^2+25t+80 gives the height of a ball in feet T seconds after it is thrown from a platform. What is the initial velocity when the ball is thrown?
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The equation h(t)=-16t^2+25t+80 gives the height of a ball in feet T seconds after it is thrown from a platform. What is the initial velocity when the ball is thrown?

The equation h(t)=-16t^2+25t+80 gives the height of a ball in feet T seconds after-example-1
User Hertzi
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6.8k points

2 Answers

5 votes

Answer: 25

Explanation:

User Anand Saga
by
6.9k points
5 votes

Answer:

25

Explanation:

-16t^2+vt+s

v=initial velocity

User CoreyRS
by
7.3k points
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