Question

How many moles of KCIO3 must completely react to produce 6 moles of O2?

Answer 1

Hello!

The answer is:

4 moles of
`KClO_(3)` are required to produce 6 moles of
`O_(2)`

Why?

To solve stoichiometric problems, we need to write the balanced equation of the compound that we are working with.

Potassium chlorate decomposition is given by the following equation:

`2KClO_(3)->3KCl+3O_(2)`

Now, from the equation we know that 3 moles of
`O_(2)` gives 2 moles of
`2KClO_(3)`, we can calculate how many moles of the same compound react to produce 6 moles of
`O_(2)` the following equation:

`(No.molKClO_(3))/(6molO_(2))=(2molKClO_(3))/(3molO_(2))\\\\No.molKClO_(3)=6molO_(2)*(2molKClO_(3))/(3molO_(2))\\\\No.molKClO_(3)=4molKClO_(3)`

Hence, we have that 4 moles of
`KClO_(3)` are required to produce 6 moles of
`O_(2)`

Have a nice day!