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Find the perimeter A(2,2),(6,-2),(5,1)​

User Bakamike
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1 Answer

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Answer:

4√2 + 2√10

Explanation:

Finding the perimeter here involves finding three point-to-point distances and then adding them up.

From (2, 2) to (6, -2) we have a change in x of 4 and a change in y of -4. We use the Pythagorean Theorem to determine the distance, which is the hypotenuse of a right triangle:

√( [4]² + [-4]² ) = 4√2. This is the length of the side connecting (2, 2) and (6, -2).

From (6, -2) to (5, 1), the distance is √( [-1]² + 3² ), or √10.

From (5, 1) to (2, 2), the distance is √( [-3]² + 1² ), or √10.

The perimeter is the sum of these three distances and is:

4√2 + √10 + √10, or 4√2 + 2√10

User Verona
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