Question

Multiply 6x^2-4x-5(2x^2+3x)

Answer 1

`\large\boxed{6x^2-4x-5(2x^2+3x)=-4x^2-19x}`

Explanation:

`6x^2-4x-5(2x^2+3x)\qquad\text{use the distributive property}\\\\=6x^2-4x+(-5)(2x^2)+(-5)(3x)\\\\=6x^2-4x-10x^2-15x\qquad\text{combine like terms}\\\\=(6x^2-10x^2)+(-4x-15x)\\\\=-4x^2-19x`

Answer 2

Step-by-step explanation:

I learned to solve these with a box method.

6x^2 -4x -5

2x^2

3x

with this method you add the matching terms

6x^2 -4x -5

2x^2 | 1 | 2 | 3

3x | 2 | 3 | 4

6x^2 -4x -5

2x^2 | 12x^4 | -8x^3 | -10x^2

3x | 18x^3 | -12x^2 | -15x

12x^4 + 10x^3 - 22x^2 - 15x