Question

Sqrt2y-5+8=4 what Is the root

Answer 1

The root of
`√(2y-5) +8 = 4` is 10.5.

Explanation:

Given that,

`√(2y-5) +8 = 4`

As we have a square root term along with a single term on left side. We will move the single term on right side.

`√(2y-5)  = 4-8`

`√(2y-5)  = -4`

Taking the square on both sides, we get

`(√(2y-5))^2  = (-4)^2`

Square will cancel the impact of square root, therefore:

`({2y-5})  = 16`

`2y = 16+5`

`2y = 21`

`y = (21)/(2)`

`y = 10.5`

Therefore, the root of
`√(2y-5) +8 = 4` is 10.5.