Question

The figure below is a net for a triangular prism. Side a = 22 feet, side b = 14 feet, side c = 13 feet, side d = 13 feet, and side e = 19 feet. What is the surface area of this figure?

A. 1,194 square feet
B. 908 square feet
C. 1,172 square feet
D. 1,216 square feet

Answer 1

the answer is 1,194

Explanation:

what you want to do is find the area of 2 triangles and 3 rectangles

area of 1st rectangle

1 = ae

=(22 ft) (19 ft)

=418 sq. ft.

area of 2nd rectangle

2 = ab

=(22 ft.) (14 ft.)

=308 sq. ft.

area of 3rd rectangle

3=ad

=(22 ft.) (13 ft.)

=286 sq. ft.

area of 1st triangle

Area of triangle = 1/2 cb

=1/2 (13ft) (14ft)

= 1/2 (182 sq. ft)

=91 sq. ft.

***this would be the same for 2nd triangle*** 91 sq ft.

Next add all areas together to get the total surface area

Total surface area = ae + ab + ad + 2 (1/2 cb)

= 418 sq. ft + 308 sq. ft. + 286 sq. ft. + 2(91 sq. ft)

=418 + 308 + 286 + 182

= 1,194 sq. ft.