Question

A sample of gas has a volume of 25L at a pressure of 200 kPa and a temperature of 25°C. What would be the volume if the pressure were increased to 250 kPa and the temperature were decreased to 0°C?​

Answer 1

Using the combined gas law, we can find that the new volume of the gas would be approximately 22.62 L.

Step-by-step explanation:

In order to find the new volume of the gas when the pressure is increased to 250 kPa and the temperature is decreased to 0°C, we can use the combined gas law.

The combined gas law states that for a given amount of gas, the ratio of pressure, volume, and temperature remains constant:

P1V1/T1 = P2V2/T2

Plugging in the values given in the question, we have:

200 kPa * 25 L / (25 + 273) K = 250 kPa * V2 / (0 + 273) K

Simplifying and solving for V2, we find:

V2 = (200 kPa * 25 L * 273 K) / (250 kPa * (25 + 273) K)

V2 ≈ 22.62 L

Answer 2

18 L

Step-by-step explanation:

Use ideal gas law:

PV = nRT

Find initial number of moles, but first convert to units that match the gas constant units.

(200,000 Pa) (0.025 m³) = n (8.314 Pa m³ / mol / K) (25 + 273.15 K)

n = 2.017 mol

At the new pressure and temperature:

(250,000 Pa) V = (2.017 mol) (8.314 Pa m³ / mol / K) (0 + 273.15 K)

V = 0.018 m³

V = 18 L