Answer:
75 %
Step-by-step explanation:
If we take the genotype of both parents who are both heterozygous, the resulting cross would be:
Hh x Hh
Punnett square:
H h
H HH Hh
h Hh hh
As you can see thre are 3 possible genotypes and 2 phentypes:
HH 1 Cloven hooves
Hh 2 Cloven hooves
hh 1 Mule hooves
Because cloven hooves is dominant, it will be expressed even with the presence of the recessive allele.
So the probability is 3 out 4 or 75%