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A spring has a spring constant of 113 N/m . How much elastic potential energy is stored in the spring when it is compressed by 0.03 m?A:0.23 j B:0.022 j C:0.051 j D: 1.70 j

User Kurohige
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2 Answers

2 votes

Answer:

= 1.7 Joules

Step-by-step explanation:

The electrical potential energy is given by;

P.E = 1/2 ke²

Where, k is the spring constant, e is the extension

Therefore;

Electrical potential energy = 1/2 × 113 N/m × 0.03 m

= 1.695 Joules

= 1.7 J

User Nrhode
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6.4k points
4 votes

Answer:

0.051 J

Step-by-step explanation:

K = 113 N/m

y = 0.03 m

The elastic potential energy of the system is given by

U = 1/2 K y^2 = 0.5 x 113 x 0.03 x 0.03 = 0.051 J

User Catandmouse
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8.3k points