Question

Simplify the expression (x^19 times y^21) divided by (x^2 times y^6)^2

Answer 1

`x^(15).y^(9)`

Explanation:

`(x^(19) . y^(21))/((x^2. y^6)^2) \\\\Here\,\, exponent\,\, rules\,\, will\,\, be\,\, used.\\First\,\, multiply\,\, power\,\, of \,\,2\,\, with\,\, denominator \,\,exponents\\\\(x^(19) . y^(21))/(x^4. y^(12))\\If \,\, same\,\, bases\,\, are\,\, divided\,\, then\,\, their\,\, exponents\,\, are \,\,subtracted\,\,\\\\x^(19-4).y^(21-12)\\\\x^(15).y^(9)`