For this case we must find the inverse of the following function:
![f (x) = \sqrt [3] {x + 12}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ksknb7dry7ds5sfv4b22elia3d9pimgsnj.png)
For this, we follow the steps below:
Replace f (x) with y:
![y = \sqrt [3] {x + 12}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/22rzkwx5fp4ndvbwuunxxcgpqziyt55kiv.png)
We exchange the variables:
![x = \sqrt [3] {y + 12}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jkoffx117m30v9i2ac0ejxkv9ba4cnyutk.png)
We solve the equation for "and":
![\sqrt [3] {y + 12} = x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s1atpegz8gzf6p98muwd309jamzrzzpkkb.png)
We raise both sides of the equation to the cube to eliminate the root:
![(\sqrt [3] {y + 12}) = x ^ 3\\y + 12 = x ^ 3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7t8bhlea6zf8dxi3qcuol23yxcvddavyjw.png)
We subtract 12 on both sides of the equation:

Thus, the inverse function is:

Answer:
Option B