Question

Factor -2bk^2 + 6bk - 2b.

-2b(k^2 - 3k - 1)
-2b(k^2 + 3k + 1)
-2b(k^2 - 3k + 1)

Answer 1

For this case we must factor the following expression:

`-2bk ^ 2 + 6bk-2b`

It is observed that the three terms have in common a ce divisible between 2 and the variable "b".

Then, we can extract common factor "2b":

`2b (-k ^ 2 + 3k-1)`

If we take out common factor "-" we have:

`-2b (k ^ 2-3k + 1)`

Answer:

Option C

Answer 2

-2b(k²-3k+1)

Explanation:

The question is on factorization

-2bk²+6bk-2b

Factor out 2b

-2b(k²-3k+1)

When you open brackets to check the answer

-2b×k²-2b×-3k-2b×1= -2bk²+6bk+2b