First exercise
Given

We can cross multiply this equation to get

Expand both terms:

Subtract 2x from both sides:

Subtract 3 from both sides:

Divide both sides by 7:

Second exercise
Let
be the number of pine, oath and ash trees. We are given:

We can substitute the expression for p of the first equation in the last equation to get

Now we use the second equation, to express o in terms of a:
