Question

Joe tries to neutralize 125mL of 2.0 M HCL with 175mL of 1.0M NaOH. will the neutralization reaction be completed? If not what is the pH of the final solution?

Answer 1

1) The neutralization reaction will mot be completed.

2) pH = 0.6.

Step-by-step explanation:

1) Will the neutralization reaction be completed?

For the neutralization reaction be completed; The no. of millimoles of the acid must be equal the no. of millimoles of the base.

The no. of millimoles of 125 mL of 2.0 M HCl = MV = (2.0 M)(125.0 mL) = 250.0 mmol.

The no. of millmoles of 175 mL of 1.0 M NaOH = MV = (1.0 M)(175.0 mL) = 175.0 mmol.

∴ HCl will be in excess.

∴ The neutralization reaction will mot be completed.

2) If not what is the pH of the final solution?

[H⁺] =[ (MV)HCl - (MV)NaOH]/V total = (250.0 mmol - 175.0 mmol) / (300.0 mL) = 0.25 M.

∵ pH = - log[H⁺]

∴ pH = - log(0.25) = 0.6.