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How much heat in kilojoules has to be removed from 225g of water to lower its temperature from 25.0oC to 10.0oC?

User Vel Genov
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1 Answer

3 votes

Answer:

14108 J

Step-by-step explanation:

The heat that has to be removed from the water is given by


Q=m C_s \Delta T

where

m = 225 g is the water mass


C_s = 4.18 J/gC is the specific heat capacity of the water


\Delta T=10.0 C-25.0 C=-15.0 C is the charge in temperature of the water

Substituting into the equation, we find


Q=(225 g) (4.18 J/gC) (-15.0 C)=-14,108 J

and the negative sign means the heat is removed from the system.

User Rozart
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