Answer:
find heat released by the burn:
(2 g) (19.4 kJ/g) = 38.8 kJ released
find heat gained by the water:
dH = m C dT
dH = (2250 g) (4.184 J/g-C) (+ 3.17 C)
dH = 29,842 Joules
aka
dH water = + 29.8 kJ
find the missing heat given to the calorimeter
(38.8 kJ released) - (29.8 kJ given to water) = 9.0 kJ given to calorimeter
What is the heat capacity of the empty bomb calorimeter
(9.0 kJ given to calorimeter) / (3.17 C rise in temp) = 2.84 kJ / C