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Calculate [H3O+

] of a 0.150 M acetic acid solution.​

1 Answer

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Answer:

[H3O+] = 0.00520 M

Step-by-step explanation:

The dissociation of acetic acid in water is given by the equation;

CH3COOH + H2O<-------> H3O+ + CH3COO-

ka = [H+][C2H3O2-]/[HC2H3O2]

Ka = 1.8 x 10^-5

= x^2 / 0.150-x

x = [H3O+]= 0.00520 M

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