Question

Using point slope form write the equation of the line that passes through the point (-1/2, 1/2) and has a slope of -1

Answer 1

y = -x

Explanation:

Given in the question,

co-ordinate(-1/2 , 1/2)

gradient of the line = -1

Standard equation form of a straight line

y - y1 = m(x - x1)

here y1 = 1/2

x1 = -1/2

m = -1

Plug values in the equation

y - 1/2 = -1(x + 1/2)

y -1/2 = -x - 1/2

y = -x

Answer 2

Answer:
`y-(1)/(2)=-(x+(1)/(2))`

Explanation:

The point-slope form of the equation of the line is:

`y-y_1=m(x-x_1)`

Where "m" is the slope of the line and
`(x_1,y_1)` is a point of the line.

You know the value of the slope and you also know a point of the line, then you need to substitute values into
`y-y_1=m(x-x_1)`.

Therefore, you get that the equation of this line in point-slope form is:

`y-(1)/(2)=-1(x-(-(1)/(2))\\\\y-(1)/(2)=-(x+(1)/(2))`