Question

What is the equation, in slope-intercept form, of the line that is perpendicular to the line

y – 4 = –(x – 6) and passes through the point (−2, −2)?

y = –x –
y = –x +
y = x – 1
y = x + 1

Answer 1

`c. \: y = x - 1`

Answer 2

y=x

Explanation:

the line that is perpendicular to the line

y – 4 = –(x – 6) and passes through the point (−2, −2)

Given equation of a line is y-4 = -(x-6)

write the equation in the form of y=mx+b where 'm' is the slope

y-4= -x+6

add 4 on both sides

y=-x+10

Slope of given line = -1

Take negative reciprocal to get the slope of perpendicular line

slope of perpendicular line = 1

slope = 1 and point (-2,-2)

y-y1= m(x-x1)

y+2= 1(x+2)

y+2=x+2

Subtract 2 from both sides

y=x