Answer:
P = 0.332
Explanation:
The probability of having the disease is 0.08
The probability that the test predicts with accuracy is 0.7.
We need to find the probability that the test positive for the disease.
Several cases may occur.
Case 1.
You have the disease and the test predicts it accurately

Case 2
You do not have the disease and the test predicts that you have it

Then the probability that the test predicts that you have the disease is the union of both probabilities P1 and P2
