Question

A 200 N force is applied to a 50.0 kg object moving at 3.0 m/s. How fast will it be going at 4.0 s?

Answer 1

19.0 m/s

Step-by-step explanation:

First of all, we can find the acceleration of the object by using Newton's second law:

`F=ma`

where

F = 200 N is the net force applied to the object

m = 50.0 kg is the mass of the object

a is the acceleration

Solving for a,

`a=(F)/(m)=(200 N)/(50.0 kg)=4.0 m/s^2`

Now we can find the final speed of the object:

`v=u+at`

where

u = 3.0 m/s is the initial speed

a = 4.0 m/s^2 is the acceleration

t = 4.0 s is the time

Substituting,

`v=3.0 m/s + (4.0 m/s^2)(4.0 s)=19.0 m/s`