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What change in volume results if 80.0 mL of gas is cooled from 84 °C to 57.0 °C?

User Danielrvt
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1 Answer

2 votes

Answer:

73.95 mL.

Step-by-step explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have two different values of V and T:

V₁T₂ = V₂T₁

V₁ = 80.0 mL, T₁ = 84.0°C + 273 = 357.0 K.

V₂ = ??? mL, T₂ = 57.0°C + 273 = 330.0 K.

∴ V₂ = V₁T₂/T₁ = (80.0 mL)(330.0 K)/(357.0 K) = 73.95 mL.

User Aynur
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