Question

Solve: 8x2 + 64x = 0.

Answer 1

x = 0 or x = -8

Explanation:

`8x^2+64x=0\qquad\text{divide both sides by 8}\\\\(8\!\!\!\!\diagup x^2)/(8\!\!\!\!\diagup)+(64\!\!\!\!\!\diagup^8 x)/(8\!\!\!\!\diagup)=(0)/(8)\\\\x^2+8x=0\qquad\text{distribute}\\\\x(x+8)=0\iff x=0\ or\ x+8=0\\\\x+8=0\qquad\text{subtract 8 from both sides}\\x=-8`