Answer:
0.267
Explanation:
This can be solved using the binomial probability formula which is:
![P(success)=nCk*p^(k)(1-p)^(n-k)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hv36prbt02dx7w1m9lol8h3d1mhaiy6lbq.png)
Where
n is total number of trials (here, the total number of questions is 8, so n = 8)
k is the number of attempts we are looking for (here, we want to find probability of 1 question correct, so k = 1)
p is the probability of success (here, success is getting a questions right. Since there are 4 choices and 1 is right, probability of right = 1/4)
Plugging all the info into the formula we get:
![P(success)=nCk*p^(k)(1-p)^(n-k)\\P(1QuestionRight)=8C1*((1)/(4))^(1)(1-(1)/(4))^(8-1)\\P(1QuestionRight)=(8!)/((8-1)!*1!)((1)/(4))((3)/(4))^7\\P(1QuestionRight)=(8!)/(7!*1!)((1)/(4))((3)/(4))^7\\P(1QuestionRight)=8((1)/(4))((3)/(4))^7\\=0.267](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4g7v1gz6wvsm03ujrlvquvab3cps02mkyg.png)
Second choice is right.