Answer:
Part a) Each friend will receive
![(3)/(10)\ pounds](https://img.qammunity.org/2020/formulas/mathematics/college/bb8uh2fefrw62sojuoazarpa2e4qwg2eyi.png)
Part b)
or
![0.95\ pounds](https://img.qammunity.org/2020/formulas/mathematics/college/9zhd6zm806cb8o6zvf57sijfyqokd3gy5w.png)
Explanation:
Part a)
we know that
To calculate the weight of peanuts in pounds that each friend will
receive, divide the total pounds of peanuts by two
so
![((3/5))/(2)=(3)/(10)\ pounds](https://img.qammunity.org/2020/formulas/mathematics/college/plqfweuecsi12y381qtrjswkpx7092tzij.png)
Part b)
Let
x-----> pounds of extra peanuts the friend needs to end up with 2 pounds of peanuts
we know that
![2=x+(3)/(10)+(3)/(4)](https://img.qammunity.org/2020/formulas/mathematics/college/tw2e41bhe25fki66mhjbmjgutq15tpze9g.png)
Solve for x
![x=2-((3)/(10)+(3)/(4))](https://img.qammunity.org/2020/formulas/mathematics/college/9n66vszzb4l3y57werxtjyfk3xokfplzls.png)
Multiply by 40 both sides
![40x=80-(12+30)](https://img.qammunity.org/2020/formulas/mathematics/college/wi95xbr9nm1lext3830um4zw016gk1xjx9.png)
![40x=38](https://img.qammunity.org/2020/formulas/mathematics/college/5p0q1tfwwz7cd0nhdxeyo3llizqyyrg1zn.png)
![x=(38)/(40)\ pounds](https://img.qammunity.org/2020/formulas/mathematics/college/i0wgro04bmej6qaibzg2vt11ow8hg4mzp5.png)
Simplify
or
![x=0.95\ pounds](https://img.qammunity.org/2020/formulas/mathematics/college/pupjrlix79z1pgtfaaogu0l80i4cyarb4u.png)