Answer:
Surface area =
![261.6cm^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g87m0d0rggl73kxuaebewjuvy4docfsvqx.png)
Volume =
![281.2cm^3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qrx0m3dnwyplt1dvk3q6dr0qgyq5im7waa.png)
Explanation:
To find the surface area of our cone, we are using the formula for the surface area of a cone:
![A=\pir(r+√(h^2+r^2) )](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rfn16vjr2ibvosi0mg91e6bwba76oa5rrm.png)
where
is the surface area
is the radius
is the height
Notice that the height, radius, and slant height make a right triangle, so to find the height,
, we can use the Pythagorean theorem:
![s^2=r^2+h^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bmlsj6ef9rznuuc8hf51h4g3o8q84a3y17.png)
![14^2=4.5^2+h^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e0mqodznukk29curwftglha2ub5y2j4jm8.png)
![196=20.25+h^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/14ua2x09fvtgfi7tp46beoovcvzdgmim0p.png)
![h^2=196-20.25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ccskgehfyn7xzyk68z96w5im4fhn0m9vfk.png)
![h^2=175.75](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s93coaqbkkar9olo69qx88x3bz6f9y4vta.png)
![h=√(175.75)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bzsej0t659zs1epfvoz67yp8h9x95wmsxs.png)
cm
We have all we need now to find the surface area of our cone:
![A=\pir(r+√(h^2+r^2) )](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rfn16vjr2ibvosi0mg91e6bwba76oa5rrm.png)
![A=\pi(4.5)(4.5+√(13.26^2+4.5^2) )](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uxadt9ykeoytag6w332nv0ctdatiilw9zn.png)
Now, to find the volume of our cone, we are using the formula for the volume of a cone:
![V=(\pi r^2h)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sqo1uc2yekgdrc7yr1buh24zgtduz7b48o.png)
where
is the volume
is the radius
is the height
Replacing values
![V=(\pi (4.5^2)(13.26))/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w66aoj2sdtsz9a0iq93dvqfxy5ul1c8uz0.png)
![V=281.2cm^3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2150bhgxpq8tdui324tywymasjud41mua3.png)
We can conclude that the surface area of our cone is 261.6 square centimeters and its volume is 281.2 cubic centimeters.