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Cw 11.1 11.4 round to the tenths

Cw 11.1 11.4 round to the tenths-example-1
User ElGavilan
by
5.7k points

2 Answers

5 votes

QUESTION.1

The area of the shaded region equals area of the bigger rectangle minus area of the smaller rectangle.

By equation, area of a rectangle
=l* w

This implies that the area of the bigger rectangle
=236*105


=24780ft^2

Also,the area of the smaller rectangle
68*42


=2856 ft^2

Hence,area of the shaded region
=24780-2856=21924ft^2

QUESTION.2

The polygon is a trapezium.

The area of a trapezium is given as;


(1)/(2)*(a+b)* h

where a and b denote the the two parallel sides and h denotes the height

From the question
a=40, b=48, h=36

By substitution,the area of the trapezium


=(1)/(2)*(40+48)*36=(1)/(2)*88*36=1584 sq.units

QUESTION 3

The polygon is a trapezium.

The area of a trapezium is given as;


(1)/(2)*(a+b)* h

where a and b denote the the two parallel sides and h denotes the height

From the question
a=6, b=20, h=8

By substitution,the area of the trapezium


=(1)/(2)*(6+20)*8=(1)/(2)*26*8=104 sq.units

QUESTION 4

The polygon is a parallelogram.

The area of a parallelogram is given as;


A=b* h

where b denotes of the length of any base and h denotes the height

From the question b=14 and h=9

By substitution,the area of the parallelogram


A=14*9=126sq.units

QUESTION 5

The polygon is a rhombus.

The area of a rhombus is given as;


A=s^2

where s is the length any side

From the question the value of s is 9

By substitution,the area of the rhombus


A=9^2=81 sq.units

QUESTION 6

The polygon is a kite.

The area of a kite is given as;


A=(1)/(2)(a* b)

where a and b denote the length of the two diagonals

From the question
a=7+7=14


b=24+7=31

By substitution,the area of the kite


A=(1)/(2)(14*31)=217sq.units

QUESTION.7

The polygon is a triangle.

The area of a triangle is given as;


A=(1)/(2)(b* h)

where b is length of the base and h denotes the length of the h of the height.

From the question
b=15


h=9

By substitution,the area of the triangle


A=(1)/(2)(15*9)=67.5sq.units

QUESTION.8

The area of a triangle is given as;


A=(1)/(2)(b* h)

where b is length of the base and h denotes the length of the height.

From the question
b=12inches


h=x and the area,
A=36in^2

By substitution,


36=(1)/(2)(12* x)


\implies 36=6x

Dividing both sides by 6


\implies x=6inches

QUESTION. 9

The area of a kite is given as;


A=(1)/(2)(a* b)

where a and b denote the length of the two diagonals

From the question
a=10yards


b=x=? and area,
A=100yd^2

By substitution,


100=(1)/(2)(10* x)

this implies that
100=5x

Multiplying both sides by
(1)/(5),

We obtain,
x=20yards

User Irmorteza
by
5.4k points
2 votes

Answer:

1. A = 21,924.0

2. A = 1,584.0

3. A = 104.0

4. A = 126.0

5. A = 81.0

6. A = 217.0

7. A = 67.5

8. x = 6.0

9. x = 20.0

Explanation:

Kindly find the attached for the step by step explanation

User Artem Selivanov
by
5.2k points