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Consider the graph of the following qyadratic equation. y=x^+4x-5 what is the axis of the symmerty?

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Answer:

The axis of symmetry is at x=-2

Explanation:

The axis of symmetry, h , is found at

h = -b/2a where a and b are the coefficients of the equation in standard form

y = ax^2 +bx +c

y = x^2 +4x+5

a =1 b=4 c=5

Then

h =- 4/2(1)

= -2

The axis of symmetry is at x=-2

User Cory Klein
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