Final answer:
The vector resulting from the operation 2v - 6u is (-52, 48). The magnitude of this vector, denoted as ||2v - 6u||, is approximately 70.77.
Step-by-step explanation:
To calculate the vector 2v-6u, we need to multiply vector v by 2, vector u by 6, and then subtract the latter from the former:
- 2v = 2(-11, 3) = (-22, 6)
- 6u = 6(5, -7) = (30, -42)
- 2v - 6u = (-22, 6) - (30, -42) = (-22 - 30, 6 + 42) = (-52, 48)
The resulting vector is (-52, 48).
To find the magnitude of this vector, we use the formula ||a|| = √(ax2 + ay2):
- ||2v - 6u|| = √((-52)2 + (48)2)
- ||2v - 6u|| = √(2704 + 2304)
- ||2v - 6u|| = √5008
- ||2v - 6u|| ≈ 70.77
Approximately, the magnitude is 70.77.