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(3^5-3^4)(3^3+3^2)/24​

1 Answer

4 votes

Hello,

You're asking: (3^5−3^4)(3^3+3^2)/24.

First, start with the three. (3^5)

(243−3^4)(3^3+3^2)/24

Do the 3 to the power of 4.

(243−81)(3^3+3^2)

Subtract 243-81 to 162.

162(3^3+3^2)/24

Do 3^3 to get 27.

162(27+32)/24

Then, do 3^2 to 9.

162(27+9)/24.

Add 27+9 to get 36 then set up multiplication.

(162)(36)/24

Multiply.

5832/24

Divide.

Therefore, you get 243 as your final answer.

User BigBob
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