70.3k views
1 vote
If t=38.5 and s=31.4 find S. Round to the nearest tenth

If t=38.5 and s=31.4 find S. Round to the nearest tenth-example-1
User Seahawk
by
4.9k points

2 Answers

3 votes

Answer: option c.

Explanation:

You need to remember the identity:


sin\alpha=(opposite)/(hypotenuse)

The inverse of the sine function is arcsine. You need to use this to calculate the angle "S":


\alpha =arcsin((opposite)/(hypotenuse))

You know that you need to find the measure of "S" and
t=38.5 (which is the hypotenuse) and
s=31.4 (which is the opposite side), then you can substitute values into
\alpha =arcsin((opposite)/(hypotenuse))

Then, you get:


S=arcsin((31.4)/(38.5))\\\\S=54.6\°

User Mohib Arshi
by
5.1k points
6 votes

Answer:

The correct answer option is C. S = 54.6°.

Explanation:

We are given a right angled triangle with two known sides,
s and
t.

We are to find the value of the angle
S.

For that, we will use sine.


sin S = \frac { s } { t }


sin S = \frac { 3 1 . 4 } { 3 8 . 5 }


S = sin'0.815

S = 54.6°

User Infotekka
by
5.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.