Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Suppose the velocities of golf swings for amateur golfers are normally distributed with a mean of 95 mph and a standard deviation of 3.9 mph.

What is the difference in velocities between a golfer whose z-score is 0 and another golfer whose z-score is −1?

Answer 1

Answer: c) 3.9

Explanation:

The mean is 95 so it has a z-score of 0

The standard deviation is 3.9 so a z-score of -1 is a velocity of 95 - 3.9

So, the difference in the their velocities is: 3.9