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A sample of gas has an initial volume of 3.97 L at a pressure of 709 mmHg . If the volume of the gas is increased to 5.36 L , what is the pressure

User Gianni Alessandro
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1 Answer

21 votes
21 votes

Answer:

525 mmHg

Step-by-step explanation:

If all other variables are held constant, you can find the pressure using Boyle's Law. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can plug the given values into the equation and simplify to find "P₂".

P₁ = 709 mmHg P₂ = ? mmHg

V₁ = 3.97 L V₂ = 5.36 L

P₁V₁ = P₂V₂ <----- Boyle's Law

(709 mmHg)(3.97 L) = P₂(5.36 L) <----- Insert values

2814.73 = P₂(5.36 L) <----- Simplify left side

525 = P₂ <----- Divide both sides by 5.36

User Jaaksarv
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