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HELP ME PLEASE ‼️‼️‼️‼️‼️

HELP ME PLEASE ‼️‼️‼️‼️‼️-example-1

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Answer:

Explanation:

Derivatives problem! I love these!

To maximize revenue: Find where R(p) has a maximum

1. Find the derivative

-4p^2 + 2000p - 3000

= (2)(-4p) + (1)2000 - (0)3000

= -8p + 2000

2. Find where the derivative = 0

-8p + 2000 = 0

2000 = 8p

250 = p

a. Price = 250

3. Plug in p to your original equation

-4(250)^2 + 2000(250) - 3000

= 247,000

b. Maximum revenue: $247,000

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