Question

Citric acid (H3 C6 H5 O7) is a product of the fermentation of sucrose (C12 H22 O11) in air.

C12 H22 O11(aq) + 3 O2(g) yields 2 H3 C6 H5 O7(aq) + 3 H2 O

Determine the mass of citric acid produced when 2.50 mol C12 H22 O11 is used.


Please show all the steps you took to get the answer!

Answer 1

960.6175

Step-by-step explanation:

The balanced equation shows that for every mole of sucrose used, 2 moles of citric acid are produced.

So 2.5 moles of C12H22O11 will produce 2*2.5 moles of Citric acid.

So 2.5 moles of C23H22O11 will produce 5 moles of Citric Acid.

The next step is to figure out the molar mass of Citric Acid.

There are

Hydrogen: H3 + H5 moles of hydrogen in 1 mole of Citric Acid = 8 mol H

Carbon: 1 mol of Citric Acid has 6 moles of Carbon in it = 6 mol C

Oxygen: 1 mol of Citric Acid has 7 moles of Oxygen it it =7 mol O

Hydrogen has a mass of 1 so Citric Acid has 1 * 8 grams H 8

Carbon has a mass of 12 so Citric Acid has 12 * 6 grams C 72

Oxygen has a mass of 16 so Citric Acid has 16 * 7 grams O 112

Total grams for 1 mol Citric Acid 192

The official published mass of Citric Acid is 192.1235 so because I used rounded numbers I'm a little off. It is important for any chemistry student student to know where the 192.1235 came from rather than exactly why I'm a little out. Every periodic table lists different masses for each element. If you want a better number, you will have to consult your own periodic table.

1 mol of Citric Acid = 192 grams

5 mols of Citric Acid = x

Cross multiply

1 * x = 5 * 192

x = 960 grams.

If you want to use the published amount then the answer will be 5 * 192.1235 = 960.6175