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Find three consecutive even integers whose sum is -48

User Sgargan
by
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2 Answers

5 votes

Answer:

-15, -16, -17

Explanation:

For three consecutive integers, we can divide the sum by 3 to find the middle integer. Then subtract 1 to get the first integer and add 1 to get the third integer.

-48 ÷ 3 = –16

–16 -1 = –15

–16 +1 = –17

User Jeff Dickey
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5 votes
Three consecutive even integers can be represented by x, x+2, x+4. The sum is 3x+6, which is equal to 108. Thus, 3x+6=108.
User Tdragon
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