Thank you for any help!

Question

asked Apr 15, 2020 26.4k views

2 Answers

Skaak · Answer 1 · 2020-04-18T20:43:52+0000

Answer:

D. No. (0, 0) satisfies
but does not satisfy
$y\leq x^2-4$ .

Explanation:

We are given the following system of equations and we are to determine if (0, 0) is its solution or not:

$y\leq x^2-4$

y>2x-1

Substituting the given point
(0, 0) in both the equations to check if it satisfies them.

$y\leq x^2-4$
$\implies$
$0\leq (0)^2-4 \implies 0\leq -4$ - False

$y>2x-1 \implies 0 > 2(0)-1 \implies 0>-10$ - True

Therefore, the correct answer option is D. No. (0, 0) satisfies
but does not satisfy
$y\leq x^2-4$ .